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sammy [17]
3 years ago
10

The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-20(c-

3)^2+180P(c)=−20(c−3) 2 +180
Mathematics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

The current that produces maximum power is 3A

Step-by-step explanation:

Given

P(c) = 20(c - 3)^2

Required [Missing from the question]

The current that produces maximum power

First, we represent the function in standard form

P(c) = 20(c - 3)^2

P(c) = 20(c - 3)(c - 3)

Open bracket

P(c) = 20(c^2 -6c+ 9)

P(c) = 20c^2 -120c+ 180

The maximum value of c is:

Max(c) = \frac{-b}{2a}

Where:

f(x) = ax^2 + b^2 + c

By comparison: P(c) = 20c^2 -120c+ 180

a = 20

b = -120

c = 180

So, we have:

Max(c) = \frac{-b}{2a}

Max(c) = \frac{-(-120)}{2 * 20}

Max(c) = \frac{120}{40}

Max(c) = 3

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