What subsets are of 64
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The required length of the hypotenuse of the triangle is √19.
<h3>What is a right triangle?</h3>- A right triangle, sometimes known as a right-angled triangle, or more formally an orthogonal triangle, formerly known as a rectangle triangle, is a triangle with one right angle or two perpendicular sides.
To find the required length of the hypotenuse of the triangle:
Legs in the right triangle refer to the perpendicular and base.
Hypotenuse:
Therefore, the required length of the hypotenuse of the triangle is √19.
Know more about right triangles here:
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First we are going to find the Area of the pond using the area of a circle formula: 
where
is the area of the circle
is the radius of the circle
We know for our problem that the pond will have a 6-foot radius, so
. Lets replace that value on our area formula:
We know that the <span>cost of installing the pond is $0.62 per square foot, so lets multiply the area we just found by the cost:
Total cost of pund=</span>
dollars
Now, let
be the width the rectangle, so its length will be 
. Remember that the area of a rectangle is width times length, so:
Since the cost of installing ties is $1, the cost of installing ties in our rectangle will be x^2+13x dollars.
<span>Stacy can spend no more than $536 on this project, so we can setup an inequality relating the cost of the pound and the cost of installing ties:
</span>
We can conclude that the inequality that can be used to fin the width,, of the patio is
where
We know for our problem that the pond will have a 6-foot radius, so
We know that the <span>cost of installing the pond is $0.62 per square foot, so lets multiply the area we just found by the cost:
Total cost of pund=</span>
Now, let
Since the cost of installing ties is $1, the cost of installing ties in our rectangle will be x^2+13x dollars.
<span>Stacy can spend no more than $536 on this project, so we can setup an inequality relating the cost of the pound and the cost of installing ties:
</span>
We can conclude that the inequality that can be used to fin the width,