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2 years ago

What subsets are of 64

Mathematics

1 answer:

scoundrel [369]2 years ago

3 0

(), (64)
i think that these are the subsets but im not completely sure

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In triangle abc shown below side ab is 6 and side ac is 4

kaheart [24]

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

7 0

2 years ago

Whats the answer and equation to Two more than four times a number is -10

Artist 52 [7]

2+4a=-10

First, subtract 2 from both sides.

4a=-12

Then divide 4 from both sides.

a=-3

hope it helps!

3 0

3 years ago

Position to term rule of 2, 6, 10, 14, 18<br><br> multiply by _____ and subtract by _____

andreyandreev [35.5K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

2, 6, 10, 14, 18

An arithmetic sequence has a constant difference and is defined as

$\:a_n=a_1+\left(n-1\right)d$

compute the differences of all the adjacent terms

$6-2=4,\:\quad \:10-6=4,\:\quad \:14-10=4,\:\quad \:18-14=4$

The difference between all the adjacent terms is the same.

Thus,

$d=4$

and

$a_1=2$

Therefore, the nth term is computed by:

$a_n=4\left(n-1\right)+2$

$a_n=4n-2$

Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.

4 0

2 years ago

Can someone help me please I need the mode, median, range and the mean.?

Neko [114]

Answer:

First the mode. Since 5 popped up the most, 5 is the mode.

Next is the median. I crossed 1 dot from each side until it shows the last dot, and 5 was the last one.

After that the range. 9-2=7

Finally the worst, the mean... 2+2+3+3+3+4+5+5+5+5+5+6+6+6+8+9+9+9+9

=104/19=5.47

SO, Mode=5 Median=5 Range=7, and the mean is 5.47 (rounded nearest hundred)

7 0

2 years ago

What is the constant of proportionality for the equation y=1 1/2x?

Dimas [21]

Answer:

<h3>hope it helps you see the attachment for further information... </h3>

<h3>regards..... </h3>

6 0

2 years ago

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