Pls help with this business

Blue Spruce Corp. accumulates the following cost and net realizable value data at December 31. Inventory Categories Cost Data Ne

Kruka [31]

Answer:

Company's total inventory 30,850

Camaras: 10,960

Camcorders: 8,850

DVDs: 11,040

Explanation:

Camaras:

cost: 10,960

net realizable value: 12,060

Camcorders:

cost: 8,850

net realizable value: 9,170

DVDs:

cost: 12,100

net realizable value: 11,040

Company's total inventory

10,960 + 8,850 + 11,040 = 30,850

We must pick between the historic cost or the net realizable value the lower. The reasoning behind this is the conservatism accounting principle to keep the assets valued at minimum.

3 0

3 years ago

Violet, William, and Xavier are partners in a partnership that sells medical devices. Violet and William each contributed $100,0

mafiozo [28]

Answer:

d. purchase the machine because each partner has one vote in management matters

Explanation:

Since in the question it is mentioned that the partners vote whether or not to buy a new machine for $100 so the violet and William would agree on this but Xavier does not agree

Now according to this situation the machine should be purchased as each partner vote is necessary also there is a majority of 2 person to buy the machine

hence, the option d is correct

8 0

3 years ago

Nash's Trading Post, LLC uses the percentage of receivables basis to record bad debt expense and concludes that 3% of accounts r

skelet666 [1.2K]

Answer:

(a) Prepare the adjusting journal entry to record bad debt expense for the year with Allowance for Doubtful Account of $ 3,041

Dr Bad Debt Expenses $10,150

Cr Allowance for doubtful debt $10,150

(b) Prepare the adjusting journal entry to record bad debt expense for the year with Allowance for Doubtful Account of $ 918

Dr Bad Debt Expenses $14,109

Cr Allowance for doubtful debt $14,109

Explanation:

The Allowance for Doubtful Account will have the Balance of : 439,700 x 3% = $13,191

(a): Bad Debt Expenses needs to be recorded: 13,191 - 3,041 = $10,150

(b): Bad Debt Expenses needs to be recorded: 13,191 + 918 = $14,109

3 0

3 years ago

NEED HELP WILL GIVE BRAINLIEST!!

mina [271]

Answer:

C

Explanation:

4 0

3 years ago

Read 2 more answers

A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

5 0

3 years ago