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Kitty [74]
3 years ago
7

Lilly was working on a report on Italian and Spanish scientists. She decided to find a 96 percent confidence interval for the di

fference in mean age at the time of significant scientific discoveries for Italian versus Spanish scientists. She found the ages at the time of science discovery of all the members of both groups and found the 96 percent confidence interval based on a t-distribution using a calculator. The procedure she used is not appropriate in this context because
The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.
The sample sizes for the two groups are not equal.
Age at the time of science discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same.
Age at the time of science discovery is likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not valid.
Age at the time of science discovery is likely to have a few large outliers, so the assumption for using this confidence interval formula is not valid.
A t statistic was used to conduct a test of the null hypothesis H0: µ = 11 against the alternative Ha: µ ? 11, with a p-value equal to 0.042. A two-sided confidence interval for µ is to be considered. Of the following, which is the largest level of confidence for which the confidence interval will NOT contain 11?
A. A 90% confidence level
B. A 92% confidence level
C. A 96% confidence level
D. A 97% confidence level
E. A 98% confidence level
Mathematics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

The answer is "Option A and Option B".

Step-by-step explanation:

In question 1:

In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.

This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.

In question 2:

When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.

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Hannah is 3 years older than twice her brother Joey’s age. Joey is 2 years old. How old is Hannah? Show all of your work!
DaniilM [7]

Answer:

7

Step-by-step explanation:

twice for joey's age so joeys age is 2 double that it will be 4 so 3+4=7

5 0
3 years ago
On a Sunday night, there are four people on a bus. The bus has five stops left before it end sits route. Suppose each person wil
allochka39001 [22]

There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>

1-  5 ways

2- 5/16

3- 1/16

4- 1/16

In the question given above n= 5 p =1/2 q= 1/2  r is the given point.

  1. <u>Part 1:</u>

The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore

nCr= 5C4= 5 ways

<u>2. Part 2:</u>

The probability that all four people get off the bus on the first stop is given by :

P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16

<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.

P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16

<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.

P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16

For binomial distribution click

brainly.com/question/15246027

brainly.com/question/13542338

3 0
3 years ago
The answers is what I got but it said it was wrong. can anyone hhelp find the right answer?​
klio [65]

Answer:

but its right

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm
Andreyy89
Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34

a(2) = a + d = 34 + 7 = 41.

4 0
4 years ago
Explain how to multiply the following whole numbers 21 x 14
Lesechka [4]

Answer:

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Step-by-step explanation:

Given

21\:\times \:14

Line up the numbers

\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

Multiply the bold numbers:    1×4=4

\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}

Multiply the bold numbers:    2×4=8

\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the top number by the bolded digit of the bottom number

\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the bold numbers:    1×1=1

\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}

Multiply the bold numbers:    2×1=2

\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}

Add the rows to get the answer. For simplicity, fill in trailing zeros.

\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}

adding portion

\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}

Add the digits of the right-most column: 4+0=4

\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}

Add the digits of the right-most column: 8+1=9

\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}

Add the digits of the right-most column: 0+2=2

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Therefore,

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

6 0
3 years ago
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