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wel
3 years ago
13

How do you prove a parallelogram using these 2 triangles, somebody needs to explain this to me?

Mathematics
1 answer:
Bingel [31]3 years ago
8 0

RQP=ONP

Since R is the midpoint of MQ, then MR and RQ are equal.

Since R is the midpoint of MQ, then P must be the midpoint of NQ

The triangles are congruent and the trapezoid is three or those triangles.

RQR reflected is a triangle inside the trapezoid. The triangles at the left and right of the trapezoid are congruent.

Since all the triangles are the exact same, then they have the same height and same length.

So you connect them without like sliding a triangle up a little bit.

The 4 congruent triangles add up to be a parallelogram.

I don't know if this is what you learned in class or where ever you did learn it but this is my way (not where-I-learned-it-from's way).

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I am confused on who to find a linear equation
Alborosie
Hope it can solve you problem... :)

7 0
3 years ago
I need help with numbers 2,3,4,5,6 I need to graduate so help
Neporo4naja [7]

Answer:

2.

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

*note* you can simplify the above further (by rationalizing them), but I think it's probably fine to leave them as is *

3.) g15.9

4.)25.4

5.) 70.8

6.) 36.4

Step-by-step explanation:

Cot is the inverse of toa so cot= adj/opp

This means the traingle's adjacent side is √3 and its opposite is 5

with this information let's figure out the hypotonouse

√3²+5²=c²

3+25=c²

28=c²

√28=c

√28=2√7

which means the triangle's

opposite= √3

hypotonous= 2√7

Adjacent= 5

With all of this we can just plug in the numbers to find the missing information (where α=angle or theta)

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

For this one we have the adjacent and need the opposite

we will use TOA

Tan(25)=x/34

34tan(25)=x

x=15.9

4.) For this one we have the adjacent but need the hypotonouse

we will use CAH

cos(48)=17/x

17/cos(48)=x

x=25.4

5.) for number 5 we have the oppsite and hypotonouse and so we'll use SOH

sin(α)=17/18

α=70.8

6.) For this one we have the opposite and adjacent and so we'll use TOA

Tan(α)=(31/42)

α=36.4

8 0
3 years ago
A line has an undefined slope and includes the points (n, - 5) and (4,1). What is the value of n?
Shalnov [3]

Answer:

n=4

Step-by-step explanation:

To get an undefined slope, the denominator has to be zero

m= (y2-y1)/ (x2-x1)


This means that x2-x1 = 0

or x2=x1

So 4=n

7 0
3 years ago
ZA and ZB are supplementary angles. If m_A
KatRina [158]

Answer:

∠A = 107

∠B = 73

Step-by-step explanation:

∠A ,  ∠B are supplementary. So, ∠A + ∠B = 180

5x + 27 + 5x - 7 = 180

5x + 5x  + 27 - 7 = 180       {Combine like terms}

             10x + 20=180

                    10x = 180 -20

                   10x = 160

                      x = 160/10

x = 16

∠A = 5x + 27 = 5*16 + 27 = 80 + 27 = 107

∠B = 5x - 7 = 5*16 - 7 = 80 - 7 = 73

5 0
3 years ago
An above ground swimming pool is leaking. After 1/2 hour the pool has leaked 7/8 of a gallon of water. How many gallons of water
pshichka [43]
7/8 gallon of water/ (1/2 hr)= 1.75 gallons of water/ hr.

The swimming pool is leaking 1.75 gallons of water/ hr.

Hope this helps~
8 0
3 years ago
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