I think it is (5, -4)... not completely sure though
Answer:
Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).
As, DO is Dilation of Δ ABC by Scale factor of
.
Vertices of A' B'C' are
![A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})](https://tex.z-dn.net/?f=A%27%3D%28%5Cfrac%7B-4%7D%7B2%7D%2C%5Cfrac%7B3%7D%7B2%7D%29%3D%28-2%2C%5Cfrac%7B3%7D%7B2%7D%29%2C%20B%27%3D%28%5Cfrac%7B4%7D%7B2%7D%2C%5Cfrac%7B4%7D%7B2%7D%29%3D%282%2C2%29%2C%20C%27%3D%28%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B1%7D%7B2%7D%29)
So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.
The two triangles will be congruent.
AO is Dilated by a factor of half , so A'O' will be half of AO.
So, correct Statements are
1. AB is parallel to A'B'.
2.DO,1/2(x, y) =
The distance from A' to the origin is half the distance from A to the origin.
Answer:
12+8.2n, this is the answer
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