I believe that it’s the first one
A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:

A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is
12√6 square units.
Answer:
2x+12=24
first you subtract 12 from both sides
2x+12=24
-12. -12
The 12-12 should cancel itself, the rest of the equation you bring down to get
2x=12 (because 24-12=12)
Now you have 2x=12.
you then divide 2x by both sides.
2x=12
/2x=/2x
The 2x/2x cancels itself out so you then solve for 12/2x.
For this you just divide 12/2 which is 6!
x= 6 is your final answer.
to check this equation you can plug your number back into x to see if it is true! 2(6)+12=24.
6 times 2 is 12 and 12+12 is 24 so your answer (6) is true!
hope this helps! :D
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R
<span>(DOS= difference of two squares, PST=perfect square trinomial </span>
<span>Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.</span>
Answer:
y = 8
Step-by-step explanation:
Step 1: Write equation
3 - 5y = -37
Step 2: Subtract 3 on both sides
-5y = -40
Step 3: Divide both sides by -5
y = 8