Can you have a triangle with sides 6, 7, and 2?
1 answer:
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Midpoint Formula = 
We are given the coordinates: A(-5,6) and B(3,2)
Plug the values into the equation to get:
M = ((3 - 5)/2, (2 + 6)/2)
Now, just solve it down to get M = (-1,4).
The midpoint of the segment with endpoints A(-5,6) and B (3,2) is (-1,4). Hope this helps ALot and have a wonderful day!
We are given the coordinates: A(-5,6) and B(3,2)
Plug the values into the equation to get:
M = ((3 - 5)/2, (2 + 6)/2)
Now, just solve it down to get M = (-1,4).
The midpoint of the segment with endpoints A(-5,6) and B (3,2) is (-1,4). Hope this helps ALot and have a wonderful day!
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
=
[ 2a₁ + (n - 1)d ]
where a₁ is the initial value and d the common difference
Given
=
[ 10 + (n - 1)3 ]
Then by comparison
2a₁ = 10 ( divide both sides by 2 )
a₁ = 4 ← initial value
and d = 3 ← common difference
Thus
=
[ 10 + (7 × 3) ]
= 4(10 + 21)
= 4 × 31
= 124