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2 years ago

How many pairs of while numbers have the sun of 110?

Mathematics

1 answer:

hammer [34]2 years ago

5 0

I'm not sure but I think it's 110÷4=27

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(9,3) and (-4,-7) whats the slope

omeli [17]

Answer:

10/13

Step-by-step explanation:

-7-(3)

----------

-4-(9)

3 0

2 years ago

Read 2 more answers

A shipment of 23 television sets contain three defective ones. In how many ways can a vending machine purchase four of these uni

Alex_Xolod [135]

$\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \neq \sqrt{x} \sqrt[n]{x}$

4 0

2 years ago

Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordi

Advocard [28]

There are a number of ways this can be done. One that is fairly simple is as follows.

Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.

Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.

Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.

The total area of the entire figure is then

... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.

7 0

3 years ago

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshme

vovangra [49]

Answer:

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

Step-by-step explanation:

Step:-1

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshmen.

μ = 35

small sample size n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

Null hypothesis :- The difference between x⁻ and μ is not significant

Alternative hypothesis:- The difference between x⁻ and μ is significant

that is μ ≠ 35

Level of significance :-∝ =0.05

The test statistic:-

$t = \frac{x^{-} - population mean}{\frac{S}{\sqrt{n} } }$

substitute all values in above equation

μ = 35 ,n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

$t = \frac{30 - 35}{\frac{10}{\sqrt{20} } }$

t= -2.235

|t| = 2.235

The degrees of freedom γ =n-1 =20-1 =19

By tabulated value of 't' for 19 degrees of freedom at 5% level of significance.= 2.093 for two tailed test.(see attached diagram below)

conclusion:-

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

8 0

3 years ago

Line m has a slope of -3. Another line n is parallel to line m. What is the slop of line n?

mina [271]

Answer:

I think its also -3

because its parallel

7 0

3 years ago