All categories

3 years ago

Which function has the same graph as x + y = 112 OA x) = -y + 11 OB. f(x) = -x + 11 Oc. x) = x- 11 O D. x) = y-11

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

4 0

Answer:

B. f(x) = -x + 11

Step-by-step explanation:

First if you rearrange the equation you get f(x) = -x + 11, like this:

x + y = 11

Minus x from both sides

y = -x + 11

F(x) and y are interchangeable so we just put f(x) in

f(x) = -x + 11

Each of the graphs are attached and we see that they are the same!

Hope this helps!!

- Kay

You might be interested in

Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.

IRINA_888 [86]

Answer:

Jane traveled 8 miles farther then her trainer

Step-by-step explanation:

The Pythagora's Theorem

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

$c^2=a^2+b^2$

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

$c=\sqrt{16^2+12^2}$

$c=\sqrt{256+144}=\sqrt{400}=20$

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0

3 years ago

Help asap plssss i have rsm in 2 hrs

rodikova [14]

Answer:

x=58cm

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

SIMPLYFY THE EXPRESSION WRITE THE ANSWER AS A POWER (5^4)^3

Anastaziya [24]

Answer:

5^12

Step-by-step explanation:

You multiply both roots

5 0

3 years ago

The tangent line to y= f(x) at (4,-6) passes through the point (10,9) Compute the following, f(4) and f'(4)

Anni [7]

The solution to your problem is as follows:

The tangent line passes through (4,-6), so x = 4 when y = -6

=> f(4) = -6

The tangent line will have a constant gradient.

gradient is m = (-6 - 9)/(4 - 10) => 5/2

Equation is y - 9 = (5/2)(x - 10)

=> y - 9 = (5/2)(x-10)

i.e. y = (5/2)(x-10) + 9
 y = (5/2)x - 25 + 9 = y = (5/2)x - 16

Now, f '(x) = dy/dx = 5/2

so, f '(4) = 5/2....i.e. gradient is 5/2 whatever the value of x.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

3 0

3 years ago

Help asap plssssssssss

Kryger [21]

Step-by-step explanation:

distance AB is (using Pythagoras with the coordinate differences between both points as sides and the distance as Hypotenuse = baseline of the triangle, the side opposite of the 90 degree angle):

distance² = (5 - -10)² + (7-2)² = 15² + 5² = 225 + 25 = 250

distance = sqrt(250)

to split this distance into a 3/2 ratio, we need actually 3+2=5 equal parts. and then AM gets 3 off these parts, and MB gets 2 of these parts.

so,

distance/5 = sqrt(250)/5 = sqrt(250/25) = sqrt(10)

so,

AM = 3×sqrt(10) = sqrt(90),

and

MB = 2×sqrt(10) = sqrt(40)

now, we need to calculate back using the same Pythagoras approach (calling the coordinates of M xm and ym)

AM² = (xm - -10)² + (ym - 2)² = (xm+10)² + (ym-2)² = 90

90 = xm² + 20xm + 100 + ym² - 4ym + 4

MB² = (5 - xm)² + (7 - ym)² = 40

40 = 25 - 10xm + xm² + 49 - 14ym + ym²

as a first approach we calculate AM² - MB²

90 = xm² + 20xm + ym² - 4ym + 104

- 40 = xm² - 10xm + ym² - 14ym + 74

----------------------------------------------------

50 = 0 + 30xm + 0 + 10ym + 30

20 = 30xm + 10ym

2 = 3xm + ym

ym = 2 - 3xm

this we use now e.g. in the first equation for AM.

90 = xm² + 20xm + (2-3xm)² - 4×(2-3xm) + 104

-14 = xm² + 20xm + 4 - 12xm + 9xm² - 8 + 12xm

-10 = 10xm² + 20xm

-1 = xm² + 2xm

xm² + 2xm + 1 = 0

solving such a squared equation

xm = (-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = 2

c = 1

xm = (-2 ± sqrt(4 - 4))/2 = -1

only one combined solution (as a squared equation usually has 2 solutions).

ym = 2 - 3xm = 2 - 3×-1 = 2 + 3 = 5

so, M = (-1, 5)

8 0

3 years ago

Which function has the same graph as x + y = 112 OA x) = -y + 11 OB. f(x) = -x + 11 Oc. x) = x- 11 O D. x) = y-11​

Which function has the same graph as x + y = 112 OA x) = -y + 11 OB. f(x) = -x + 11 Oc. x) = x- 11 O D. x) = y-11