Equivalent expressions are expressions of equal values
The equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
<h3>How to determine the equivalent expressions</h3>
The first expression has been solved.
So, we have the following expressions
4x−7y−5z+6 and -3x−8y−4−87z
<u>4x−7y−5z+6</u>
We have:
4x-7y-5z+6
Rewrite as:
4x+ (y - 8y) + (2z-5z) +6
<u>-3x−8y−4−87z</u>
We have:
-3x−8y−4−87z
Rewrite as:
3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Hence, the equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Read more about equivalent expressions at:
brainly.com/question/2972832
Baso 6 divided by 2 is 3 that’s what the question is saying
Answer:
a. 0.6899
b. 0.1642
Step-by-step explanation:
a. Given the probability of success is 0.94 for an expert and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:

Hence, the probability of correctly identifying the 6 matches is 0.6899
b.Given the probability of success is 0.74 for a novice and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:

#Hence, the probability of correctly identifying the 6 matches is 0.1642
*I have used the sample size of 6(due to conflicting info/question size).
There is so solution to this problem
<h3>
Answer: Choice A</h3>
![x^2\left(\sqrt[4]{x^2}\right)](https://tex.z-dn.net/?f=x%5E2%5Cleft%28%5Csqrt%5B4%5D%7Bx%5E2%7D%5Cright%29)
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Explanation:
The fourth root of x is the same as x^(1/4)
I.e,
![\sqrt[4]{x} = x^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%20%3D%20x%5E%7B1%2F4%7D)
The same applies to x^10 as well
![\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%5Cleft%28x%5E%7B10%7D%5Cright%29%5E%7B1%2F4%7D)
Multiply the exponents 10 and 1/4 to get 10/4
![\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%5Cleft%28x%5E%7B10%7D%5Cright%29%5E%7B1%2F4%7D%20%3D%20x%5E%7B10%2A1%2F4%7D%20%3D%20x%5E%7B10%2F4%7D)
![\sqrt[4]{x^{10}} = x^{10/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20x%5E%7B10%2F4%7D)
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If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below
![x^{m/n} = x^a\sqrt[n]{x^b}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20x%5Ea%5Csqrt%5Bn%5D%7Bx%5Eb%7D)
The 'a' and 'b' are found through dividing m/n
m/n = a remainder b
'a' is the quotient, b is the remainder
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The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4
m/n = 10/4 = 2 remainder 2
We have a = 2 and b = 2
So
![x^{m/n} = x^a\sqrt[n]{x^b}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20x%5Ea%5Csqrt%5Bn%5D%7Bx%5Eb%7D)
turns into
![x^{10/4} = x^2\sqrt[4]{x^2}](https://tex.z-dn.net/?f=x%5E%7B10%2F4%7D%20%3D%20x%5E2%5Csqrt%5B4%5D%7Bx%5E2%7D)
which means
![\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%7Bx%5E2%7D%20%5Csqrt%5B4%5D%7Bx%5E2%7D)