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love history [14]
3 years ago
6

Find the distance between the two points rounding to the nearest tenth (if

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
Distance: (sqroot(x2-x1)^2 + (y2-y1)^2)
sqroot(1-3)^2 + (8-6)^2
sqroot(-2)^2 + (2)^2
sqroot(4) + 4
Square root of 8 = 2.82843
Round to nearest tenth
Solution: 2.8
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Rochelle can run 800 meters in 5 minut
Semmy [17]
To find how much she can run in one minute we’re going to divide 800 by 5, to which we get 160.

She runs 160 meters in one minute.

We want to know how many meters she can run in 9 minutes.

160 * 9 = 1,440

She can run 1,440 meters in 9 minutes.
8 0
3 years ago
Help please!!!! ;-; staph scrolling
sertanlavr [38]

y = 4^x \quad \to\quad y = - \frac 2 3 (4^{x+7}) - 5

y=4^x

OK, we'll go in steps.  First a reflection through the x axis, which negates y.

y = -4^x

Now a vertical scaling of 2/3

y = -\frac 2 3 \cdot 4^x

Now we shift seven units to the right,

y = -\frac 2 3 \cdot 4^{x+7}

Now down five,

y = -\frac 2 3 \cdot 4^{x+7} - 5

There it is.

Answer: reflection thru x axis, vertical scale 2/3, right shift 7, down 5, second choice

8 0
4 years ago
Es matemáticas, suma y resta de fracciones <br><br> Ayuda porfa
Vesnalui [34]

\bold{\huge{\purple{\underline{ Solutions }}}}

<h3><u>Solution </u><u>(</u><u>a)</u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{6}}{\bold{ + }}{\bold{\dfrac{ 2}{5}}}

  • <u>By </u><u>taking </u><u>LCM </u><u>of </u><u>the </u><u>given </u><u>denominators </u>

\sf{ = \:}{\sf{\dfrac{ 35 +  12 }{30}}}

\sf{ =\: }{\sf{\red{\dfrac{ 47 }{30}}}}

Hence, The answer is 47/30

<h3><u>Solution </u><u>(</u><u> </u><u>b</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 1}{7}}{\bold{ + }}{\bold{\dfrac{ 1}{8}}}

  • <u>By taking LCM of the given denominators </u>

\sf{ =\: }{\sf{\dfrac{ 8 + 7 }{56}}}

\sf{ =\: }{\sf{\red{\dfrac{ 15}{56}}}}

Hence, The answer is 15/56

<h3><u>Solution </u><u>(</u><u> </u><u>c</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{13}}{\bold{ + }}{\bold{\dfrac{ 5}{10}}}

  • <u>By taking LCM of the given denominators </u>

\sf{=\:}{\sf{\dfrac{ 70 + 65 }{130}}}

\sf{ = \:}{\sf{\dfrac{ 135}{130}}}

\sf{ =\:}{\sf{\red{\dfrac{ 27}{26}}}}

Hence, The answer is 27/26

<h3><u>Solution </u><u>(</u><u> </u><u>d</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{5}}{\bold{ - }}{\bold{\dfrac{ 1}{3}}}

  • <u>By taking LCM of the given denominators</u>

\sf{ =\:}{\sf{\dfrac{ 21 - 5 }{15}}}

\sf{ = \:}{\sf{\red{\dfrac{ 16}{15}}}}

Hence, The answer is 16/15

<h3><u>Solution </u><u>(</u><u> </u><u>e) </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 8}{7}}{\bold{ - }}{\bold{\dfrac{ 9}{11}}}

  • <u>By taking LCM of the given denominators</u>

\sf{=\:}{\sf{\dfrac{ 88 - 63}{77}}}

\sf{=\:}{\sf{\red{\dfrac{ 25}{77}}}}

Hence, The answer is 25/77

<h3><u>Solution </u><u>(</u><u> </u><u>f</u><u>) </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 11}{4}}{\bold{ - }}{\bold{\dfrac{ 1}{9}}}

  • <u>By taking LCM of the given denominators</u>

\sf{=\:}{\sf{\dfrac{ 99 - 4}{36}}}

\sf{ =\: }{\sf{\red{\dfrac{ 95}{36}}}}

Hence, The answer is 95/36

3 0
2 years ago
Read 2 more answers
-Translate this phrase into an algebraic expression.
Virty [35]

Answer:

20n - 4

Step-by-step explanation:

the product of 20 and a number means multiplying 20 by n (the variable representing the number)

to get four less than this product, you subtract 4

5 0
3 years ago
2. Which of the following inequalities is NOT true? F 0.309 &gt; 0.3 G 0.329 &gt; 0.4 H 0.104 &gt; 0.09 J 0.9 &gt; 0.890​
Greeley [361]

Answer:

I believe that G 0.329 > 0.4 is not true.

Step-by-step explanation:

0.4 is clearly a larger number than 0.329. I feel like the key point to these are the starting numbers behind the decimal. So for 0.329 the key number would be the 3, and for 0.4 the key number would be the 4. Now which one do you think is bigger? Obviously the 0.4 for G is NOT true.

5 0
3 years ago
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