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Deffense [45]
3 years ago
11

A rhombus has diagonals with lengths 6 cm and 10 cm. It’s area is ____

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

B.

Step-by-step explanation:

A = ab/2

A = (6 cm)(10 cm)/2

A = 30 cm^2

Answer: B.

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Which symbol can be used to correctly compare the two fractions 2/5 and 35/100
Kaylis [27]

Reduce 35/100 to 7/20 by dividing both sides by 5.

2/5 is bigger than 7/20.

2/5 > 7/20  or 2/5 > 35/100 if you leave it unsimplified

Hope this helps :)

5 0
4 years ago
Read 2 more answers
PLEASE HELP PRE CAL!!
Len [333]

Answer:

Width = 2x²

Length = 7x² + 3

Step-by-step explanation:

∵ The area of a rectangle is 14x^{4}+6x^{2}

∵ Its width is the greatest common monomial factor of 14x^{4} and 6x²

- Let us find the greatest common factor of 14 , 6 and x^{4} , x²

∵ The factors of 14 are 1, 2, 7, 14

∵ The factors of 6 are 1, 2, 3, 6

∵ The common factors of 14 and 6 are 1, 2

∵ The greatest one is 2

∴ The greatest common factor of 14 and 6 is 2

- The greatest common factor of monomials is the variable with

   the smallest power

∴ The greatest common factor of x^{4} and  x² is x²

∴ The greatest common monomial factor of  14x^{4} and 6x² is 2x²

∴ The width of the rectangle is 2x²

To find the length divide the area by the width

∵ The area = 14x^{4}+6x^{2}

∵ The width = 2x²

∴ The length = ( 14x^{4}+6x^{2}) ÷ (2x²)

∵  14x^{4} ÷ 2x² = 7x²

∵ 6x² ÷ 2x² = 3

∴ ( 14x^{4}+6x^{2}) ÷ (2x²) = 7x² + 3

∴ The length of the rectangle is 7x² + 3

8 0
3 years ago
Plz, Solveeeeeeeeeeeeeeeeeeee! I will give you all my points
Blababa [14]
1/2bh
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7 0
3 years ago
John needs to write 2,146 online math questions in 45 weeks. John is estimating how many questions he should write each week to
vagabundo [1.1K]

Answer: 2,000 ÷ 50

Step-by-step explanation:

From the question, we are informed that John needs to write 2,146 online math questions in 45 weeks and that he is estimating how many questions he should write each week to meet the deadline.

The compatible numbers that provide a better estimate for the number of question he should write each week, is 2,000 ÷ 50. This is because rounding up of 2146 to the nearest thousand gives 2000. The number beside the thousand place is 2 and sinces it's not up to 5, the number becomes 2000. Likewise 45 to the nearest ten gives 50 since the number beside the ten is 5, therefore 1 will be added to 4 which becomes 5 and the number in the unit place is changed to 0, this makes the number become 50.

Therefore, the answer is 2000 ÷ 50.

5 0
3 years ago
4.6p – 6.3p + 3.9 = –9.18
lozanna [386]
Are you looking for p=7.69411764
6 0
3 years ago
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