Yesterday.
Exp: if you make the denominators equal, 5/6 becomes 10/12 which is more than 7/12
Answer:
30
Step-by-step explanation:
I'm assuming you mean negative integers and mixed. -3--3=? When to negatives are back to back it turns in to a positive number. The equation becomes -3+3=0.
Adding 2 negative numbers will always result in a negative value. -3+-3=-6.
A negative times a negative is always a positive . -2x-2=4
A positive integer times a negative integer will be a negative value. -3x4=-12.
A negative divided by a negative is a negative. -12/-2=-6
A positive divided by a negative is a negative. 9/-3=-3
Answer:
a = 0
Step-by-step explanation:
The cube root (radical) is equivalent to x^(1/3). When that is divided by x^(1/3), the result is ...
(x^(1/3))/(x^(1/3)) = x^(1/3 -1/3) = x^0
Comparing that to x^a, we find a=0.
_____
The applicable rules of exponents are ...
![\sqrt[n]{x^m}=x^{\frac{m}{n}}\\\\\dfrac{x^a}{x^b}=x^{a-b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%5Cdfrac%7Bx%5Ea%7D%7Bx%5Eb%7D%3Dx%5E%7Ba-b%7D)
Answer:
(A) 180
Step-by-step explanation:
We have to treat those player selections as independent events, since one doesn't influence the other (the fact you chose Joe as a guard, shouldn't have an influence on who'll pick as center, unless there's bad blood between some players... but that's a whole other story).
So, how many ways to pick 2 guards from a selection of 4? The order doesn't seem to matter here, since they don't specify for example that Joe can only play on the left side). So, it's a pure combination calculation:

C(4,2) = 6.
How many ways to pick the 2 forwards from a group of 5? Using the same calculation, we get:
C(5,2) = 10.
And of course, the coach has 3 ways to pick a center player from 3.
Then we multiply the possible ways to pick guards, forwards and center...
6 * 10 * 3 = 180 ways.