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mylen [45]
3 years ago
13

Tell whether each system of equations has no solution or ,infinitely many solutions.​

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

x + 2 = x + 2 ⇒ Infinitely Many Solutions

3x + 1 = 3x - 10 ⇒ 1 ≠ -10 ⇒ No solutions

x + 4 = 2x + 4 ⇒ 4 = x + 4 ⇒ 0 = x ⇒ One solution

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Which of the following sequences is an arithmetic sequence?
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20 ÷ 5 = 4

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Given a non-zero rational number, a, and an irrational number, b, what can be said about the product of a and b?
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Answer:

The product of a non-zero rational number and an irrational number is irrational.

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A quadrilateral with no acute angels
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Below.

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Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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