Answer:
look at the picture for the answer
Hello!
Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.
A) x-axis, y=x, y-axis, x-axis
b) x-axis, y-axis, x-axis
c) y=x, x-axis, x-axis
d) y-axis, x-axis, y-axis, x-axis
The best answer is C180 rotation wud take that point to 4th quadrant
reflection in x-axis takes that to 1st quadrant
<span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started
</span>
Hope this Helps! :)
10+8/2-4
PEMDAS
parenthasese
exxonents
multiplication or division
addiotn or subtration next
10+8/2-4
8/2 first
4
10+4-4
add
10+4=14
minus
14-4=10
answer is 10
Answer: The missing statements are,
In first blank: ∠2≅∠1
In second blank: AC≅AC
In third blank: Reflexive
Step-by-step explanation:
Since, The hypotenuse angle theorem states that if the hypotenuse and an acute angle of one right triangle are congruent to the hypotenuse and an acute angle of another right triangle, then the two triangles are congruent to each other.
Here, given:
∠D and ∠B are right angles.
DC ║ AB
Prove: Δ ADC ≅ Δ CBA
Statement Reason
1.∠D and ∠B are right angles 1. Given
2. ∠2 ≅ ∠1 2. If lines are parallel then interior angles
are equal
3. AC≅AC 3. Reflexive
4.Δ ADC ≅ Δ CBA 4. Hypotenuse angle theorem
