The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
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Answer:
The one on the Top Left.
Step-by-step explanation:
The line is on the negative part of the graph, same as the numbers in the problem
Step-by-step explanation:
- -12=12i^2, 5
- -12-=12i^2*i^2
- 12(-4)=-48=48i^2
- -12(-5)=60
Answer: Your plotting function is linear but not proportional : Y=2x-2
Step-by-step explanation: