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Rudik [331]
3 years ago
9

Find a function rule for the line that passes through the origin (0,0) and the point (-8, -19)

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

B.

y =  \frac{19}{8} x

Step-by-step explanation:

Our slope is Rise over Run. In this case begin at the point (-8,-19) and find how many units up (rise) and how many units over (run) you must travel to reach the next point of (0,0).

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Find the distance between the points E(3, 7) and F(6,5).
zmey [24]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ E(\stackrel{x_1}{3}~,~\stackrel{y_1}{7})\qquad F(\stackrel{x_2}{6}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ EF=\sqrt{(6-3)^2+(5-7)^2}\implies EF=\sqrt{3^2+(-2)^2} \\\\\\ EF=\sqrt{9+4}\implies EF=\sqrt{13}\implies EF\approx 3.61

4 0
4 years ago
Solve the following;<br> 25 ≥ 2a -9<br> please help!!!
lianna [129]

Answer:

a ≤ 17

Step-by-step explanation:

25 ≥ 2a -9

To solve the equation above, we are going to follow the step below;

First, we will add 9 to both-side of the inequality

25 ≥ 2a -9

25 +9 ≥ 2a -9 + 9

34  ≥ 2a

To get the value of a, we will divide both-side of the inequality by 2

34/2 ≥ 2a/2

(On the right-hand side of the inequality, the 2 at the numerator will cancel-out the 2 at the denominator while on the left-hand side of the equation 34 will be divided by 2)

34/2 ≥ a

17 ≥ a

which implies: a ≤ 17

4 0
3 years ago
PLEASE HELP. NO LINKS. NEED REAL EXPLANATION.
Sveta_85 [38]

Answer:

Area: 28.26ft², Circumference: 18.84ft

Step-by-step explanation:

Area of a circle: πr²

Circumference of a circle: πd (or 2πr)

Since the diameter is 6ft, then the radius is half of that, which is 3ft. This means that our area is:

πr²

π(3)²

π(9)

9π

9(3.14)

28.26ft²

Our circumference is:

πd

π(6)

6π

6(3.14)

18.84 ft

5 0
3 years ago
Which expression is equivalent to log w (x^2 -6)^4/ 3 sqrt x^2+8?
evablogger [386]

Answer:

C 4\log_w(x^2-6)-\dfrac{1}{3}\log_w(x^2+8)

Step-by-step explanation:

First use the property of logarithms

\log _ab-\log_ac=\log_a\dfrac{b}{c}.

For the given expression you get

\log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2+8} }=\log_w(x^2-6)^4-\log_w\sqrt[3]{x^2+8}=\log_w(x^2-6)^4-\log_w(x^2+8)^{\frac{1}{3}}

Now use property of logarithms

\log_ab^k=k\log_ab.

For your simplified expression, you get

\log_w(x^2-6)^4-\log_w(x^2+8)^{\frac{1}{3}}=4\log_w(x^2-6)-\dfrac{1}{3}\log_w(x^2+8).

3 0
3 years ago
Plz help. It was already due but I need to get it done so plz help me:(
Anettt [7]

Answer:

4 and 10 - acute

2 is acute, but 3 is obtuse

8 and 12 - acute

6 and 12 - acute

1 is obtuse 2 is acute

15 and 11 are obtuse

9 is obtuse but 8 is acute

2 and 4 are acute.

Step-by-step explanation:

I believe this is correct.

A right angle is a perfect corner. Think of a square and look at the corner, it doesn't go farther or shorter when it hits a side if you know what I mean by that. An acute angle is shorter than a right angle, or stops before it can be called a right angle. An obtuse angle is bigger than a right angle, or ends after the right angle point. I hope what I have just said here helps you with future problems!! Good luck :))

6 0
3 years ago
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