The ratios 84/105 and 128/160 are proportional
<u>Solution:</u>
Given, two ratios are
and ![\frac{128}{160}](https://tex.z-dn.net/?f=%5Cfrac%7B128%7D%7B160%7D)
We have to give two different reasons to support the answer.
<em><u>Reason 1:</u></em>
Now, we know that, numerators and denominators should be proportional to be two fractions in proportion.
![\text { Then, } \frac{84}{128}=0.65625 \text { and } \frac{105}{160}=0.65625](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Then%2C%20%7D%20%5Cfrac%7B84%7D%7B128%7D%3D0.65625%20%5Ctext%20%7B%20and%20%7D%20%5Cfrac%7B105%7D%7B160%7D%3D0.65625)
So numerators and denominators are in proportion, then given two fractions are proportion.
<em><u>Reason 2:</u></em>
Now, values of two fractions must be equal:
![\rightarrow \frac{84}{105}=\frac{128}{160} \rightarrow 84 \times 160=105 \times 128 \rightarrow 13440=13440](https://tex.z-dn.net/?f=%5Crightarrow%20%5Cfrac%7B84%7D%7B105%7D%3D%5Cfrac%7B128%7D%7B160%7D%20%5Crightarrow%2084%20%5Ctimes%20160%3D105%20%5Ctimes%20128%20%5Crightarrow%2013440%3D13440)
So, values of two fractions are equal, then they are in proportion.
Hence, the given two fractions are in proportion.