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scoray [572]
3 years ago
8

Please help :)

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

The ratios 84/105 and 128/160 are proportional

<u>Solution:</u>

Given, two ratios are \frac{84}{105} and \frac{128}{160}

We have to give two different reasons to support the answer.

<em><u>Reason 1:</u></em>

Now, we know that, numerators and denominators should be proportional to be two fractions in proportion.

\text { Then, } \frac{84}{128}=0.65625 \text { and } \frac{105}{160}=0.65625

So numerators and denominators are in proportion, then given two fractions are proportion.

<em><u>Reason 2:</u></em>

Now, values of two fractions must be equal:

\rightarrow \frac{84}{105}=\frac{128}{160} \rightarrow 84 \times 160=105 \times 128 \rightarrow 13440=13440

So, values of two fractions are equal, then they are in proportion.

Hence, the given two fractions are in proportion.

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Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

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The equation is ax+r=7 <br><br>how do I solve for r??
Strike441 [17]
The solution is r= 7/a-x How did i do this?
Your equation is ax+ r=7, so the goal is to isolate the r. You begin by dividing the a from the ax. Remember, what you do to one side, you must do to the other. So you do 7/a, since you can't simplify 7/a, leave it as it is. Next, your equation should look like this x+r=7/a. In order to isolate the r, you move the x to the other side by subtracting, which leaves you with the answer of r= 7/a-x.
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3 years ago
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Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

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3 years ago
21. What is the value of x if 5:(3x+2) = 7:(5x-2).<br>A. 6<br>B. 5<br>C.7.​
KatRina [158]

Answer:

5/(3x+2) = 7/(5x-2)

<=>5*(5x-2) = 7*(3x+2) (x is not equal to -3/2 or 2/5)

<=> 25x -10 = 21x +14   (x is not equal to -3/2 or 2/5)

<=> 4x = 24                   (x is not equal to -3/2 or 2/5)

<=> x = 6 (valid)

6 0
3 years ago
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