Hello :
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
Answer:
1/20
Step-by-step explanation:
(1/5) ÷ 4
*remember, you don't divide fractions, you multiply the first fraction by the inverse (flip it upside down) of the second fraction.*
(1/5) × (1/4) = (1/20)