<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
The Answer: (-b + 15) (15 - b)
Given

Divide it by (x+1) using synthetic division, as shown below
The green line is a minus sign.
Thus,

Therefore, since the remainder is different than zero, (x+1) is not a factor of 4x^2+2x-5
Answer:
Step-by-step explanation:
Given is a function of x

When y=0 we get x=0 and infinity
Hence x intercept is 0 and one asymptote is x axis.
When x=0 , y =0


Maxima at x=1, and point of inflection is at x=2
Increasing upto x=1 and then decreases
Graph is enclosed