Which are partial products for 56 × 31?

Jenny has nine marbles, but her best friend Susie gives her ten more! However, the neighborhood bully, Danny, steals four marble

Dimas [21]

Answer:

Jenny has 50 marbles

Step-by-step explanation:

I find it easiest to right down the numbers as I read the question,

(9+10-4) x3 +7-2

8 0

3 years ago

Which is an equation of the inverse of y=3/2x?

Elenna [48]

Answer:

y

=

3

2

x

Rewrite in slope-intercept form.

Tap for more steps...

y

=

3

2

x

Use the slope-intercept form to find the slope and y-intercept.

Tap for more steps...

Slope:

3

2

y-intercept:

(

0

,

0

)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values.

Tap for more steps...

x

y

0

2

3

Graph the line using the slope and the y-intercept, or the points.

Slope:

3

2

y-intercept:

(

0

,

0

)

x

y

0

2

3

image of graph

Step-by-step explanation:

7 0

2 years ago

Please answer fast! (10 points)

SIZIF [17.4K]

Answer:

can u show me a picture of this problem.

Step-by-step explanation:

8 0

3 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

longitud del radio de la circunferencia circunscrita a un heptágono regular si su diagonal de menor longitud mide 42 cm

oksano4ka [1.4K]

Answer:

The answer is easy.

Step-by-step explanation:

6 0

2 years ago