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3 years ago

Please look at picture and help

Mathematics

2 answers:

Leya [2.2K]3 years ago

5 0

Answer:

I think it is SAS.

Step-by-step explanation:

PtichkaEL [24]3 years ago

3 0

Answer:

its d. side angle side.

hope it help u.

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Deon is running for president of the chess club, and he received 26 votes. There are 40 members in the club. What percentage

maxonik [38]

Answer:

65%

Step-by-step explanation:

13/20 =65%

7 0

3 years ago

What is the absolute value of -4/25

Y_Kistochka [10]

The absolute value of x: |x|.

|x| = x if x ≥ 0 examples: |5| = 5; |0| = 0; |8.34| = 8.34; |1/2| = 1/2

|x| = -x if x < 0 examples: |-5| = -(-5) = 5; |-8| = -(-8) = 8; |-1.2| = 1.2;

|-3/7| = 3/7

Therefore

$\left|-\dfrac{4}{25}\right|=\dfrac{4}{25}$

6 0

4 years ago

Read 2 more answers

HELP MATH ANSWER QUESTION

Marat540 [252]

Answer:A

Step-by-step explanation:

5 0

3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

Your class is learning to tie knots. Each student needs a piece of rope that is

Korvikt [17]

Answer:

6 yards of rope

Step-by-step explanation:

1 yard = 3 feet

3/8*16= 6 yards

hope this was helpful

plz mark Brainliest

im trying to rank up ;p

8 0

3 years ago