This is the concept of trigonometry, we are required to find the vertical asymptote of the function given by;
y=2tan x
For any y=tan x, vertical asymptotes occur at the point x=π/2+nπ, where is an integer given by n=0,1,2,3...
Therefore we can generate the vertical asymptotes as follows;
When x=0
y=π/2
when x=1
y=π/2+π
y=3/2π
when x=2
y=π/2+2π
y=5/2π
Therefore at the interval [0,2π]
The vertical asymptotes are:
π/2, 3/2π, 5/2π
Answer:
first step is to divide -12 by 6
Step-by-step explanation:
The first step would be to divide -12 by 6
-12/6 = -2
-2(-3) = 6
6 + 8 = 14
Answer:
Step-by-step explanation:
Review the standard equation of a circle with center at (h, k) and radius r:
(x - h)^2 + (y - k)^2 = r^2
A point on (4, -2) has the radius r^2 = (4)^2 + (-2)^2, or r^2 = 20, or r = 2√5. Knowing the center is at (0, 0), we can write:
x^2 + y^2 = 20, or x^2 + y^2 = (2√5)^2
In order to get an 81 average,
the student has to get 81x5=405
71+96+90+73+?=405
330+?=405
405-330=75
he needs to get an 75
Answer:
(2^3)^2/2^3X2^2 = 6/4 = 3/2
Step-by-step explanation:
(2^3)^2 = 6^2 = 36
2^3 X 2^2 = 6 X 4 = 24