Answer:
Yes there is evidence that Canadian high-performance male athletes are deficient in their caloric intake
Step-by-step explanation:
Expected value of one Canadian Player caloric intake is 3077 calories. Standard deviation of those players are 987. Lets consider that they fits in Gaussian distribution model. We need to find Z value to find the percentage of athletes that take more than 3421,7 calories.
As you can see at the attachment %63,7 of athletes are taking less than 3421.7 Calories.

Approximately 73 athletes are taking less than 3421.7 Calories.
14= 14
16=12
I hope I helped
Ounce of blue dye mixed with one gallon of white paint base = 3/4
Ounce of blue dye mixed with eight gallons of white paint base = 
= 3 × 2
=6
Ounce of pink dye mixed with one gallon of white paint base = 2/3
Ounce of pink dye mixed with eight gallons of white paint base = 
= 16/3
= 5.3
Hence, 6 ounce of blue dye and 5.3 ounce of pink dye are needed to mix with 8 gallons of paint.
=6
The numbers I have input, it’s seems like the answer is never.