All categories

2 years ago

Solve for a,

Mathematics

2 answers:

PolarNik [594]2 years ago

4 0

Answer:

a = -7 should be it

bixtya [17]2 years ago

3 0

<h2>Questions :- solve for a </h2>

<h3>Equation :- a +(-5) = (-12) </h3>

<h2>Answer:- </h2>

$a + ( - 5) = ( - 12) \\ a = - 12 + 5 \\ a = - 7$

You might be interested in

Maria tiene 3 yardas de cinta; necesita 1/4" de yarda de cinta para hacer cada moño. Explicar cuantos moños puedes hacer. Explic

evablogger [386]

Can't understand your language

6 0

3 years ago

The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Substitute 50 for y in the formula

5x+10y=800

5x+10*50=800

5x+500=800

5x=800-500

5x=300

x=300/5

x=60

3 0

3 years ago

Read 2 more answers

A.Directions: Solve the system of equations by substitution and elimnination. Check your solutions.

Daniel [21]

Answer:

I had done already.thanks for huge point and heart.

7 0

3 years ago

Can someone help with 11-15

lozanna [386]

Answer: -4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$

8 0

3 years ago