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Maksim231197 [3]
3 years ago
8

I'm confused, please help. :/

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

82°

Step-by-step explanation:

Angle C and B equal the measure of angle A so,

143 - 61 = 82

Angle B is 82°

vampirchik [111]3 years ago
5 0

uh i did this wrong so uh just ignore what i said

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The arc length of a sector is equal to four times the radius. Express the arc length s
Sveta_85 [38]

Answer:

Step-by-step explanation:

Given that,

The arc length is four times the radius

Let he radius be 'r'

Then, the arc length be 's'

The arc of a sector can be calculated using

s=θ/360 × 2πr

Then, given that s=4r

So, 4r = θ × 2πr / 360

Divide both side r

4 = θ × 2π/360

Then, make θ subject of formula

θ × 2π = 360 × 4

θ = 360 × 4 / 2π

θ = 720 / π

So, area of the sector can be determine using

A = θ / 360 × πr²

Since r = ¼s

Then,

A = (θ/360) × π × (¼s)²

A = (θ/360) × π × (s²/16)

A = θ × π × s² / 360 × 16

Since θ = 720 / π

A = (720/π) × π × s² / 360 × 16

A = 720 × π × s² / 360 × 16 × π

A = s² / 8

Then,

s² = 8A

Then,

s= √(8A)

s = 2 √2•A

6 0
3 years ago
CAN SOMEONE PLEASE HELP. SHOW WORK. NEED AS SOON AS POSSIBLE
Studentka2010 [4]
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4 years ago
Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
9966 [12]

L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

5 0
4 years ago
Given the equation -2x+3y=12, find the missing value in the ordered pair 3, <br><br> Noo linkss plz
astraxan [27]

Answer:

(3,6)

Step-by-step explanation:

-2x+3y=12

Let x = 3

-2(3) +3y = 12

-6+3y = 12

Add 6 to each side

-6+6 +3y = 12+6

3y = 18

Divide each side by 3

3y/3 = 18/3

y = 6

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3 years ago
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Naily [24]

Answer: t\geq 1

Step-by-step explanation:

you would multiply by 3 on both sides to get the division to go away.

then subtract 8 from both sides.

then you have your answer

5 0
3 years ago
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