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Maksim231197 [3]
3 years ago
8

I'm confused, please help. :/

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

82°

Step-by-step explanation:

Angle C and B equal the measure of angle A so,

143 - 61 = 82

Angle B is 82°

vampirchik [111]3 years ago
5 0

uh i did this wrong so uh just ignore what i said

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Elena L [17]
3x-\ pineapple\\
2x-\ mango\\\\
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3y-\ pineapple\\
5y-\ mango\\\\
3x-144=3y\ \ | add\ 144\\
2x=5y\\\\
3x=3y+144\ \ \ | divide\ by\ 3\\
2x=5y\\\\
x=y+48\\2x=5y\\\\
2(y+48)=5y\\
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3 years ago
Is (2, 4) a solution to the system<br> y = 2x<br> x + y = 6
posledela

Answer:

yes you plug the numbers in

5 0
3 years ago
37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the
Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy

and I assume <em>C</em> has a positive orientation in both cases

(a) It looks like the region has the curves <em>y</em> = <em>x</em> and <em>y</em> = <em>x</em> ² as its boundary***, so that the interior of <em>C</em> is the set <em>D</em> given by

D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}

• Compute the line integral directly by splitting up <em>C</em> into two component curves,

<em>C₁ </em>: <em>x</em> = <em>t</em> and <em>y</em> = <em>t</em> ² with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}

(b) <em>C</em> is the boundary of the region

D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}

• Compute the line integral directly, splitting up <em>C</em> into 3 components,

<em>C₁</em> : <em>x</em> = <em>t</em> and <em>y</em> = 0 with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = <em>t</em> with 0 ≤ <em>t</em> ≤ 1

<em>C₃</em> : <em>x</em> = 0 and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}

• Using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}

4 0
3 years ago
What is the perimeter? Please help
allochka39001 [22]

Answer: The answer would be D. 64

Step-by-step explanation: Understanding that the question noted that the second rectangle was dilated from PQRS, which has a perimeter of 16. With the coordinates of point P for the first rectangle being (2,0.5) whilst the second rectangle has point P at (8,2). To figure out the perimeter, divide point P from the second rectangle with point P from the first. The result would be 4. Thus, the scale factor is 4, which you then multiply the perimeter of PQRS by, which was 16. 16 times 4 equals 64.

5 0
3 years ago
Read 2 more answers
Two parallel lines are crossed by a transversal. What is the value of h? h = 60 h = 80 h = 100 h = 120
lisabon 2012 [21]
I added the diagram of the question.

<u><em>Answer:</em></u>
h = 60°

<u><em>Explanation:</em></u>
We are given that lines k and l are parallel lines.
This means that angles 120° and h are <u>supplementary angles</u>.
This means that their measures <u>add up to 180°</u>

<u>Therefore:</u>
180° = 120° + h
h = 180° - 120°
h = 60°

Hope this helps :)

8 0
3 years ago
Read 2 more answers
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