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Oxana [17]
2 years ago
8

Choose the inequality that represents the following graph.

Mathematics
2 answers:
slamgirl [31]2 years ago
8 0

Answer:

D

Step-by-step explanation:

Tcecarenko [31]2 years ago
4 0
D

Hope this helps you
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Evaluate each trigonometric equation for θ.
liberstina [14]

Answer:

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

Step-by-step explanation:

Let us revise the trigonometry functions

  • Sin(x) = opposite/hypotenuse
  • Cos(x) = adjacent/hypoteouse
  • Tan(x) = opposite/adjacent
  • Csc(x) = hypotenuse/opposit
  • Sec(x) = hypotenues/adjacent
  • Cot(x) = adjacent/opposite

In the given figure

The opposite side to angle Ф = 8

The adjacent side to angle Ф = 15

Find the hypotenuse using Pythagoras' theorem

Hypotenuse = \sqrt{8^{2}+15^{2}  }

Hypotenuse = \sqrt{64+225}

Hypotenuse = \sqrt{289}

Hypotenuse = 17

Let us use the rules above to find the trigonometry functions

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

4 0
3 years ago
I’m struggling a bit on this question, may someone help me please
Leto [7]

Answer:

k = 2

Step-by-step explanation:

Use a graphing calculator

6 0
3 years ago
Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
yan [13]
Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

8 0
3 years ago
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
sweet [91]
A conservative vector field \mathbf f has curl \nabla\times\mathbf f=\mathbf0. In this case,

\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0

so the vector field is not conservative.
3 0
3 years ago
Is 16/3 rational or irrational?
Rudik [331]
16/3 is rational simply because it is a fraction made up of whole numbers.

Irrational numbers cannot be expressed as fractions made up of whole numbers.
5 0
2 years ago
Read 2 more answers
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