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Alecsey [184]
3 years ago
15

If an object is moving at -1.7 m/s for 20 seconds what is its displacement?

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
6 0

Answer:

0.085 m

......:.:.:.:.

OlgaM077 [116]3 years ago
5 0

Answer:

0.085 m

Step-by-step explanation:

change in displ. = change in velocity ÷ change in time

so,

x = v ÷ t

= -1.7 m/s ÷ 20s

=0.085 m

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What is the factorization of the expression below?
mestny [16]

Answer:

Answer B is correct

(6x + 5)(6x - 5)

Step-by-step explanation:

36 {x}^{2}  - 25 \\  {6}^{2} {x}^{2}   -  {5}^{2}  \\  = (6x - 5)(6x + 5)

6 0
3 years ago
Mr Davis buys 30 tickets for the drama club to attend a play. The tickets cost n dollars each for a total of $360
nalin [4]

Answer:

the answer is F. because n x 30 would = 360 and the n would be 12 so he paid 12 dollars per ticket and I got that answer by dividing the two numbers 30 and 360

brainliest plz

5 0
3 years ago
What is 37 divided by 6 in fraction form
kotegsom [21]

Answer:

\frac{37}{6}  thats the answer

7 0
3 years ago
Read 2 more answers
Can I get help with this problem please?
Rashid [163]

Answer:

B

Step-by-step explanation:

To find the y- intercept let x = 0

From the table for f(x)

When x = 0 → f(x) = - 4

That is the y- intercept = - 4

Given

g(x) = 3 (2)^{x}

let x = 0 , then

g(0) = 3 (2)^{0} [ 2^{0} = 1 ]

       = 3 × 1

       = 3

That is the y- intercept = 3

Thus the y- intercept of g(x) is greater → B

8 0
3 years ago
Estimate 1 13 cos(x2) dx 0 using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. (Round your answers to six decimal
babunello [35]

Answer:

(a) 4.152698

(b) 3.215557

Step-by-step explanation:

(a)

\int\limits^{13}_1 {cos(x^2)} \, dx =M_n=$\sum_{n=1}^{\infty} f(m_i)\Delta x $

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

Now, the midpoints of these subintervals are:

\frac{1+5}{2} =3\\\\\frac{5+9}{2} =7\\\\\frac{9+13}{2} =11

Hence:

M_4= 3*(cos(3^2))+3*(cos(7^2))+3*cos((11^2))\approx 4.152698

(b)

\int\limits^{13}_1 {cos(x^2)} \, dx =T_n=\frac{\Delta x}{2} (f(x_o)+2f(x_1)+2f(x_2)+...+2f(x_n_-_1)+f(x_n))

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

The endpoints of the subintervals consist of:

5,9

Hence:

T_4= \frac{3}{2}(cos(1^2)+2*cos(5^2)+2*cos(9^2)+cos(13^2)) \approx 3.215557

8 0
3 years ago
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