Ask question

Ask question

All categories

3 years ago

15

If an object is moving at -1.7 m/s for 20 seconds what is its displacement?

2 answers:

Y_Kistochka [10]3 years ago

6 0

Answer:

0.085 m

......:.:.:.:.

OlgaM077 [116]3 years ago

5 0

Answer:

0.085 m

Step-by-step explanation:

change in displ. = change in velocity ÷ change in time

so,

x = v ÷ t

= -1.7 m/s ÷ 20s

=0.085 m

You might be interested in

Use the drop-down menus to complete each question so the statement about its solution is true.

spin [16.1K]

Step-by-step explanation:

• no solution:

3x+9+4x+x = 8x + 9

• one solution:

3x+9+4x+x = 7x + 11

• infinitely many solutions:

3x+9+4x+x = 8x + 11

4 0

3 years ago

Please help me. I need help.

vagabundo [1.1K]

Answer:

28

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the equation of the line that passes through the point (-8,1) and has a slope of -3/4

ioda

Answer:

y=-3/4-5

Step-by-step explanation:

plug in ordered pair 1= -3/4(-8)+b

solve for b. b= -5

plug in to y=mx+b

3 0

3 years ago

Read 2 more answers

Oranges sell for $5.00 per bag. If there are 10 oranges in each bag, how much is the price per orange?

yulyashka [42]

Answer:

The answer is A

Step-by-step explanation:

10 divided by 5

8 0

3 years ago

Read 2 more answers

The coordinates G(7,3), H(9, 0), (5, -1) form what type of polygon?

Marrrta [24]

Answer:

Is an acute triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

G(7,3), H(9, 0), I(5, -1)

step 1

Find the distance GH

substitute in the formula

$d=\sqrt{(0-3)^{2}+(9-7)^{2}}$

$d=\sqrt{(-3)^{2}+(2)^{2}}$

$GH=\sqrt{13}\ units$

step 2

Find the distance IH

substitute in the formula

$d=\sqrt{(0+1)^{2}+(9-5)^{2}}$

$d=\sqrt{(1)^{2}+(4)^{2}}$

$IH=\sqrt{17}\ units$

step 3

Find the distance GI

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(5-7)^{2}}$

$d=\sqrt{(-4)^{2}+(-2)^{2}}$

$GI=\sqrt{20}\ units$

step 4

Verify what type of triangle is the polygon

we know that

If applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$ ----> is a right triangle

$c^{2}> a^{2}+b^{2}$ ----> is an obtuse triangle

$c^{2}< a^{2}+b^{2}$ ----> is an acute triangle

where

c is the greater side

we have

$c=\sqrt{20}\ units$

$a=\sqrt{17}\ units$

$b=\sqrt{13}\ units$

substitute

$c^{2}= (\sqrt{20})^{2}=20$

$a^{2}+b^{2}=(\sqrt{17})^{2}+(\sqrt{13})^{2}=30$

therefore

$c^{2}< a^{2}+b^{2}$

Is an acute triangle

6 0

3 years ago

Read 2 more answers