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xxMikexx [17]
3 years ago
12

3x+2y=10 and 2x+3y=-3

Mathematics
1 answer:
defon3 years ago
8 0

Answer: x =  −2 /3 y +  10 /3  and x =  −3/ 2 y +  −3 /2

Step-by-step explanation:

1. 3x+2y=10

3x+2y=10

3x+2y+−2y=10+−2y

3x=−2y+10

3x /3  =  −2y+10 /3

x =  −2 /3 y +  10 /3

2. 2x+3y=−3

2x+3y=−3

2x+3y+−3y=−3+−3y

2x=−3y−3

2x /2 = −3y−3/2

x =  −3/ 2 y +  −3 /2

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Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

7 0
3 years ago
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