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2 years ago

3x+2y=10 and 2x+3y=-3

Mathematics

1 answer:

defon2 years ago

8 0

Answer: x = −2 /3 y + 10 /3 and x = −3/ 2 y + −3 /2

Step-by-step explanation:

1. 3x+2y=10

3x+2y=10

3x+2y+−2y=10+−2y

3x=−2y+10

3x /3 = −2y+10 /3

x = −2 /3 y + 10 /3

2. 2x+3y=−3

2x+3y=−3

2x+3y+−3y=−3+−3y

2x=−3y−3

2x /2 = −3y−3/2

x = −3/ 2 y + −3 /2

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What is 800-5x divided by 6.5

MA_775_DIABLO [31]

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

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3 years ago

Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin

NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

Assuming that $\bar X =5.5$ and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=1086-1=1085$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that $t_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139$

$5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861$

So on this case the 95% confidence interval would be given by (5.139;5.861) We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

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Step-by-step explanation:

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zheka24 [161]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

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