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Ivan
3 years ago
14

I will cash app u $20 dollars show your work thank u

Mathematics
1 answer:
kolezko [41]3 years ago
3 0

Answer:

hmm.. very blurry repost please

Step-by-step explanation:

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7m - 17 = -24<br> what is m?
aev [14]

Answer:

Move all terms that don't contain

m

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857142

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3 0
3 years ago
Aline passes through (-3,-2) and is perpendicular to 3x - 2y = 7.
Natali5045456 [20]

Answer:

y=-\frac{2}{3}x-4

Step-by-step explanation:

3x-2y=7

-3x      -3x

-2y=-3x+7

/-2      /-2

y=\frac{3}{2}x-\frac{7}{2}

perpendicular lines always have opposite reciprocal slopes

3/2--> -2/3

y=-2/3x+b

-2=-2/3(-3)+b

-2=2+b

-2    -2

b=-4

y=-2/3x-4

8 0
3 years ago
Read 2 more answers
A large interquartile range shows the data is
lukranit [14]

A large interquartile range shows the range in values of the central 50% of the data.

3 0
3 years ago
A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

8 0
3 years ago
Find the reciprocal of the following:<br><br> a. 12 b. 3 1/4 c. - 9
Eva8 [605]

Answer:

b. 3 1/4

Step-by-step explanation:

8 0
3 years ago
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