Simplify the expression 5(n^2+n)-3n(2n^2+4n-2)

Mathematics

1 answer:

slega [8]3 years ago

8 0

first, lets distribute the equation. 5(n^2+n)-3n(2n^2+4n-2) would become

5n^2 +5n -6n^3 -12n^2 +6n

Now we add the like terms.

-6n^3 - 7n^2 +11n

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Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
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If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is

f(x) approx. equal to [f '(c)]x + f(c)].

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f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4

Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.

What is the linearization of f(x) = (x^3)/4, if c = a = 81?

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