Answer: It would be that first one
Step-by-step explanation:
Cool I do flvs to
Answer:
125feet
Step-by-step explanation:
Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.
The arrow reaches the maximum height at dh/dt = 0
dh/dt = -32t + 80
0= -32t+80
32t = 80
t = 80/32
t = 2.5secs
substitute t = 2.5 into the formula;
h = -16t^2 + 80t + 25
h = -16(2.5)^2 + 80(2.5) + 25
h = -16(6.25)+225
h = -100+225
h = 125
Hence the maximum height the arrow reaches is 125feet
Answer:
52feet
Step-by-step explanation:
The set up will be a right angle
Let the angle of depression be 30°
The height above the sea level will be the opposite
The distance of the ship from the base is x (adjacent)
Using TOA
Tan theta = opposite/adjacent
Tan 30 = 30/x
x = 30/tan 30
x = 30/0.5774
x = 51.96
x ≈ 52 feet to the nearest foot
Answer:
In word form it would be 2 to the 6th power.
Step-by-step explanation:
We know this because exponent equals to 2*2*2*2*2*2 or also known as 2 to the 6th power.
Answer:
3 okie
Step-by-step explanation:
