Answer:
12, right?
Step-by-step explanation:
I think the declaration that three had spots may be a red herring meant to mislead you. If she has 7 after giving away 5, that would mean that in total, there are 12 cards.
Divide Total time into two Time Periods. A regular Demand and a High Demand Time Period. Since 75% of the 1,200 calls occur between 9:30 am and 3:30 pm. We multiply .75 x 1,200 to get 900. We get an average of 900 calls every day between the hours of 9:30 am and 3:30 pm – Our net time for this time period is 6 hours.
Therefore, 6 Hours/900 becomes our quotient
Again, since the denominator is larger we invert it to 900 calls/6 Hours
To get a demand of 150 calls per hour.
We need to be able to handle 150 calls per hour.
So how Many Call Representatives are needed?
Again, our historical data tells us that each person can handle 10 calls an hour.
Therefore 150 calls per hour /10 Minutes = 15 Customer Service Representatives are needed during Peak Time!
Now, Subtract the Peak Hours from the 21 Hours Net Time Per day, gives us 15 Non-Peak hours we have to staff.
Answer:
can you plz rewrite the question I want to help but I can't see it. you can even take a picture of the question.
Answer:
So, the answer in short is B) (6,1)
Step-by-step explanation:
If you graph the points, then you see that point A is 8 points away from point B on the X-axis. If you take 8 and divide it by 4, you get 2, so that means that the 1/4 way point is 2 points away from point A, giving you 6 as your x-axis point for this new point. B is the only one with 6 as its spot on the x axis, leaving B as the only choice. BTW you're pretty cute ;)
Here is the correct computation of the question.
The future lifetimes (in months) of two components of a machine have the following joint density function:
for 0 < x < 50 - y < 50, otherwise.
Write down a single integral representing the probability that both components are still functioning in 20 months from now.
Answer:
Step-by-step explanation:
From the given information;
for 0 < x < 50 - y < 50, otherwise.
We can assert that the probability is the integral of the given density over the part of the range 0 ≤ x ≤ 50 - y ≤ 50 in which both x and y are greater than 20.
From the attached file below; their shows a probability density graph illustrating the above statement being said.
Now; to determine the probability that illustrates the integral of the density ; we have : P[(X > 20)∩(Y > 20)]
In addition to that:
From the image attached below;
We look into the region where the joint density under study is said to be positive and the triangle limits by the line axis x+y = 50
∴
Thus; the single integral representing the probability that both components are still functioning in 20 months from now is