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tensa zangetsu [6.8K]
3 years ago
8

what is the explicit formula for a sequence for which the first five terms are 0, 0, 1, 5, and 23? an = (n – 1)! – 1 an = (n – 1

)! an = n! – 1 an = n!
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0
a_1=0;\ a_2=0;\ a_3=1;\ a_4=5;\ a_5=23\\\\Answer:\\\\a_n=(n-1)!-1\\becouse\\a_1=(1-1)!-1=0!-1=1-1=0\\a_2=(2-1)!-1=1!-1=1-1=0\\a_3=(3-1)!-1=2!-1=1\cdot2-1=2-1=1\\a_4=(4-1)!-1=3!-1=1\cdot2\cdot3-1=6-1=5\\a_5=(5-1)!-1=4!-1=1\cdot2\cdot3\cdot4-1=24-1=23
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given the equation y = 2x - 8, find the ordered-pair solution when x = 4 and the ordered-pair solution when y = 4
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Answer:

When x = 4, (4, 0)

When y = 4, (6, 4)

Step-by-step explanation:

To find the ordered-pair solution when x = 4, plug 4 into the x of the equation.

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y = 2(4) - 8

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This produces the ordered pair (4, 0).

To find the ordered-pair solution when y = 4, plug 4 into the y of the equation.

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4 = 2x - 8

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This produces the ordered pair (6, 4).

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