True. If the list contains any elements that appear more than once, then it has duplicate elements and the variable has_dups is True.
What is variable?
Throughout computer programming, a variable is indeed a named container for a specific set of bits or type of data. A variable is indeed an abstract storage location with an associated symbolic name that holds some unidentified quantity of information made reference to as a value. Eventually, a memory address may be used to link or identify a variable. In addition to using the variable name or the variable itself, depending on circumstances, the stored value is typically referenced by the variable name. The name can be used independently of the precise information it represents thanks to the separation of name as well as content. During run time, a value can be bound to an identification number in computer source code.
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Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
2^32 times as many values can be represented
Explanation:
32-bit. This means that the number is represented by 32 separate one’s and zero’s. 32 bits of 2 possible states = 2^32=4,294,967,296 possible values.
Integer meaning that only whole multiples of one are accepted.
Signed meaning that negative values are accepted. This halves the number of possible positive values (roughly), so the largest number you can represent is 2^31–1=2,147,483,647, but instead of 0, the smallest number you can represent is -2,147,483,648. An unsigned 32-bit integer, by contrast, can represent anything from 0 to 4,294,967,295.
Answer:
hyperlink
Explanation:
Hyperlinks render as underlined by default, so that's my guess.
Answer:
import java.util.Scanner;
public class StoreGuesses {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_GUESSES = 3;
int[] userGuesses = new int[NUM_GUESSES];
int i = 0;
for (i = 0; i < NUM_GUESSES; ++i){
userGuesses[i] = scnr.nextInt();
}
for (i = 0; i < NUM_GUESSES; ++i){
System.out.print(userGuesses[i] + " ");
}
}
}
/*
Output:
2 4 6
2 4 6
*/
