Answer:
The program in Python is as follows:
myList = []
num = int(input())
count = 0
while num>=0:
myList.append(num)
count+=1
num = int(input())
myList.sort()
mid = int((count-1)/2)
print(myList[mid])
Explanation:
This initializes the list
myList = []
This gets the first input
num = int(input())
This initializes count to 0
count = 0
The following is repeated until the user inputs a negative number
while num>=0:
This appends the input number to the list
myList.append(num)
This increments count by 1
count+=1
This gets another input
num = int(input())
This sorts the list
myList.sort()
Assume the number of inputs is odd, the middle element is calculated as
mid = int((count-1)/2)
This prints the middle element
print(myList[mid])
<em>From the complete question. the condition that ends the loop is a negative integer input</em>
The part of a computing device that is the biggest power consumer is;
Central Processing Unit
<h3>Central Processing Unit</h3>
The part of a computing device that cosnumes the most power is called the Central Processing Unit (CPU). This is due to the following reasons;
- The CPU consists of motherboard and battery that draws power from the socket.
- The Mother board is equipped with logic gates that are used to implement logic in the computer.
- The Logic gates are voltage signals that signify the binary information that are fed into the system.
Read more about Central Processing Unit (CPU) at; brainly.com/question/4558917
Thank you for being the rare question where you actually provide what language you want your answer in; I approve, and encourage this.
In Java, the following will work.
I made it a bit more versatile to work with others numbers, other than 99, if you so please (if not, just hardcode the 99 in yourself).
// Example list - fill this with numbers yourself.
ArrayList<Integer> nums = new ArrayList<>();
int n = 99;
int count = (int)nums.stream().filter(i -> i == n).count();
System.out.println(n + " occurences.");
