9 - 3 divided by 1/3 + 1

Mathematics

2 answers:

stepan [7]3 years ago

7 0

Answer:

Step-by-step explanation:

9 – 3 ÷ 1/3 + 1

9 – 3/1/3 + 1

= 9 – 3/3 + 1

= 9 – 1 + 1

= 9

9 – 3 ÷ (1/3) + 1

= 9 – 9 + 1

= 0 + 1

= 1

jolli1 [7]3 years ago

6 0

Answer:

its just 9

Step-by-step explanation:

Divide: 3 : 1 / 3 = 3 / 1 · 3 / 1 = 3 · 3 / 1 · 1 = 9 / 1 = 9 Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator,

You might be interested in

Transformation example

leonid [27]

Answer:

Rotation, Reflection, Dilation.

Step-by-step explanation:

4 0

2 years ago

Write a linear function with the values f(-1)=8 and f(5)=6

lukranit [14]

(-1,8) and (5,6) are points on the line.
Slope of line = (8-6)/(-1-5) = 2/(-6) = -⅓
y-6 = -⅓(x-5)
y = -⅓x + 5/3 + 6 = -⅓x + 7⅔

3 0

3 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$