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denpristay [2]
3 years ago
15

Graph the equations below using slope-intercept form

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Look at the picture.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

m=\dfrac{\Delta y}{\Delta x}

We have y=\dfrac{4}{5}x-1

b=-1\to(0,\ -1)

m=\dfrac{4}{5}\to\dfrac{\Delta y}{\Delta x}=\dfrac{4}{5}

<em>4 units up and 5 units right</em>

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56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(
PIT_PIT [208]

There are 2 tangent lines that pass through the point

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

Explanation:

Given:

y=\frac{x}{x+1}

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

y=m(x-1)+2 [1]

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for m:

\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\

\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}

\frac{dy}{dx}= \frac{1}{(x+1)^2}

m=\frac{1}{(x+1)^2} [2]

Substitute equation [2] into equation [1]:

y=\frac{x-1}{(x+1)^2}+2 [1.1]

Because the line must touch the curve, we may substitute y=\frac{x}{x+1}:

\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2

Solve for x:

x(x+1)=(x-1)+2(x+1)^2

x^2+x=x-1+2x^2+4x+2

x^2+4x+1

x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}

x=-2 ± \sqrt{3}

x=-2 ± \sqrt{3}<em> </em>and x=-2-\sqrt{3}

There are 2 tangent lines.

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

8 0
2 years ago
alex spent 3/7 of his money he gave 1 /4 of the remainder to his sistet he haf $120 left how much money did he in the beginning
Sonbull [250]
Let his total money be x.
He spent (3/7)*x of his money.
He gave 1/4(x-3/7x) to his sister. 
which is : (1/4)*(4/7)*x = (1/7)*x 
Now,
How much money he have in the beginning = 
(3/7)*x+(1/7)*x+120=x
(4/7)*x+120=x
120=x-(4/7)*x
120=(3/7)*x
x=120*7/3 [cross multiplication]
x=280.

So, Alex had $280 in the beginning.

6 0
3 years ago
#19 <br> Quadrilateral ABCD is a parallelogram. What is the measure of
Burka [1]

Answer:

133°

Step-by-step explanation:

In the attached file

7 0
3 years ago
how do you do this? i don't need it solved i just don't know how to do it. i know the note on the side says how to but i'm still
olchik [2.2K]

Answer:

Perimeter of triangle J= 18.0 units (3 s.f.)

Perimeter of triangle K= 19.0 units (3 s.f.)

Step-by-step explanation:

The length of each side of the triangle can be found using the distance formula below:

\boxed{d=  \sqrt{(y1- y2)^{2} + (x1 - x2)^{2}  } }

Please see the attached pictures for full solution.

5 0
3 years ago
The sides of a square field are 28 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co
Ulleksa [173]

Answer:

168.24784 m²

Step-by-step explanation:

Area of the square:

28 x 28=784 sq. m.

Area of the circle:

π(r²)=π(14)²=196π

    =615.75216

Area not covered by the sprinkler:

784-615.75216=168.24784 m²

6 0
3 years ago
Read 2 more answers
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