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ELEN [110]
3 years ago
5

What is 25% of 60 dhhsbebebebrbrbrnr

Mathematics
2 answers:
weqwewe [10]3 years ago
6 0

Answer:

15

Step-by-step explanation:

yanalaym [24]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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If the two lines y1 = -1/2x +5 and y2 = 2x + 5 were to be graphed, what would their intersection point represent?
grigory [225]

Answer:

D. Their intersection point is the only point where the same input into both functions yields the same output.​

Step-by-step explanation:

The intersection point of 2 graphed lines represents the solution.

At this point, for both lines, there is the same x value (input) and the same y value (output) because both of the lines have that point in common.

So, if those 2 lines were to be graphed, the intersection point would represent the only point with the same input and output for both functions.

D is the correct answer.

7 0
3 years ago
The coordinates of A, B,and C in the diagram are A(p,4), B(6,1), C(9,q). What equation correctly relates p and q?
murzikaleks [220]
I don't see any diagram. So, I'll just wing it.

Value of q:
p, 6, 9 ⇒ there is a difference of 3. The sequence increases by 3. So, it can be assumed that the p is equal to 3. A(p,4) ⇒ A(3,4)

Value of q:
4, 1, q ⇒ there is a difference of 3. The sequence decreases by 3. So, it can be assumed that q is equal to -2. C(9,-2)
 
        p        q
A     3        4     ⇒ 3 + 4 = 7
B     6        1     ⇒ 6 + 1 = 7
C     9       -2    ⇒ 9 + (-2) = 7

Notice that the sequence has an equation of p + q = 7.


7 0
3 years ago
Read 2 more answers
How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
  • x_2=1,\ x_3=9;
  • x_2=2,\ x_3=8;
  • x_2=3,\ x_3=7;
  • x_2=4,\ x_3=6;
  • x_2=5,\ x_3=5;
  • x_2=6,\ x_3=4;
  • x_2=7,\ x_3=3;
  • x_2=8,\ x_3=2;
  • x_2=9,\ x_3=1;
  • x_2=10,\ x_3=0.

In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
  • x_2=1,\ x_3=8;
  • x_2=2,\ x_3=7;
  • x_2=3,\ x_3=6;
  • x_2=4,\ x_3=5;
  • x_2=5,\ x_3=4;
  • x_2=6,\ x_3=3;
  • x_2=7,\ x_3=2;
  • x_2=8,\ x_3=1;
  • x_2=9,\ x_3=0.

In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
  • for x_1=4 - 7 solutions;
  • for x_1=5 - 6 solutions;
  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
  • for x_1=9 - 2 solutions;
  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0
3 years ago
Read 2 more answers
Find the errors and correct the following mathematical sentences.​
matrenka [14]

Answer:

This is your answer

4 0
3 years ago
2. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the near
hoa [83]
Given:
angle of 6 : i'm assuming this is 6 degrees.
distance of 5 miles.

tan(6) = rise/5 mi
rise = 5 mi * tan(6)
rise = 5 mi * 0.10510423526
rise = 0.52552117632

rise = 0.53 miles.
7 0
3 years ago
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