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Svetach [21]
2 years ago
8

1 pts

Mathematics
1 answer:
balu736 [363]2 years ago
8 0

9514 1404 393

Answer:

  $935.11

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year

  A = $850(1 +0.024/2)^(2·4) = $935.11

The amount accumulated will be $935.11 after 4 years.

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Mathematics please help...​
galben [10]

Answer:

the answer is B

Step-by-step explanation:

area of the minor arc is teter all over 360 times 2 pie r square.

that is

\frac{?}{360}  \times 2\pi {r}^{2}

= but because the question said for length AB, youvhave to use only one radius.

\frac{160}{360}  \times 2 \times  \pi \times 9

You the use 40 to cancel 160 and 360 to get 4 all over 9 times 2 pie times 9.

\frac{4}{9}  \times 2 \times \pi \times 9

You then cancel 9 with 9 to get 4 times 2 times pie

4 \times 2 \times \pi

this is equal to

8\pi

3 0
3 years ago
A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

Rate at which the man is walking,\frac{d(m)}{dt} = 2 ft/sec

Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

⇒ h=\sqrt{(2400+2700)^2+500^2} = 5124.45

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

⇒ \frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}                       ...as \frac{d(m+w)}{dt} = 5 ft/sec

⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0
3 years ago
Calculate the slope of the line.Please help!!
vladimir2022 [97]
The slope is 2/3 you’re welcome :)
5 0
3 years ago
A triangle has height 15 in. And area 120 in2. what is length of its base
Novosadov [1.4K]
Working out is in picture

4 0
3 years ago
Read 2 more answers
Use the recursive formula to answer the question.
scZoUnD [109]
You know a1.
So find a2, a3, and so on until a7.

a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
4 0
3 years ago
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