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2 years ago

8

1 pts

1 answer:

balu736 [363]2 years ago

8 0

9514 1404 393

Answer:

$935.11

Step-by-step explanation:

The amount is given by the formula ...

A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year

A = $850(1 +0.024/2)^(2·4) = $935.11

The amount accumulated will be $935.11 after 4 years.

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Mathematics please help...

galben [10]

Answer:

the answer is B

Step-by-step explanation:

area of the minor arc is teter all over 360 times 2 pie r square.

that is

$\frac{?}{360} \times 2\pi {r}^{2}$

= but because the question said for length AB, youvhave to use only one radius.

$\frac{160}{360} \times 2 \times \pi \times 9$

You the use 40 to cancel 160 and 360 to get 4 all over 9 times 2 pie times 9.

$\frac{4}{9} \times 2 \times \pi \times 9$

You then cancel 9 with 9 to get 4 times 2 times pie

$4 \times 2 \times \pi$

this is equal to

$8\pi$

3 0

3 years ago

A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500

Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking, $\frac{d(w)}{dt}$ = 3 ft/sec

Rate at which the man is walking, $\frac{d(m)}{dt}$ = 2 ft/sec

Collective rate of both, $\frac{d(m+w)}{dt}$ = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min

Now,

Distance traveled by man and woman are $m$ and $w$ ft respectively.

⇒ $m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft$

⇒ $w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\ ft$

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate $\frac{dh}{dt}$ .

Lets calculate h.

Applying Pythagoras formula.

⇒ $h^2=(m+w)^2+500^2$

⇒ $h=\sqrt{(2400+2700)^2+500^2} = 5124.45$

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ $h^2=(m+w)^2+500^2$

⇒ $2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt} + \frac{d(500)}{dt}$

⇒ $\frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}$ ...as $\frac{d(500)}{dt}= 0$

⇒ Plugging the values.

⇒ $\frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}$ ...as $\frac{d(m+w)}{dt} = 5$ ft/sec

⇒ $\frac{d(h)}{dt} =4.9761$ ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0

3 years ago

Calculate the slope of the line.Please help!!

vladimir2022 [97]

The slope is 2/3 you’re welcome :)

5 0

3 years ago

A triangle has height 15 in. And area 120 in2. what is length of its base

Novosadov [1.4K]

Working out is in picture

4 0

3 years ago

Read 2 more answers

Use the recursive formula to answer the question.

scZoUnD [109]

You know a1.
So find a2, a3, and so on until a7.

a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.

4 0

3 years ago