Answer: a) Yes b) Polygon ABCD ~ Polygon EFGH c) JKLM is 3x bigger than polygon ABCD
Step-by-step explanation:
(for part c)
JM= 36
AD= 12
36/12= 3
JKLM is 3x bigger than polygon ABCD
<span>6(-3r)=-39+3r
-18r = -39+3r
39 = 18r + 3r
39 = 21r
39/21 = r
13/7 = r
r = 13/7</span>
I believe the correct answer is 1.08
64-6= 58
58 squared= 7.6(or 7.61)
5+2= 7
7.6÷7= 1.08
Hello!
To find the quadrant of where the angle 7π/6 radians is located, we will need to convert from radians to degrees. To do that, we will need to multiply it by 180/π.
7π/6 × 180/π = 1260/6 = 210 degrees
Since 210° is between 180° and 270°, then 7π/6 radians is located in the third quadrant shown by: Quadrant III, then 180° < θ < 270°.
Therefore, 7π/6 radians is located in quadrant III.