This would be a combination I believe not a permutation so the equation to use would be nCr= n!/(n-r)!r!
So 10C2=45
The problem gives us points (4, 12) and (11,26). We first find the slope using m=(y2-y1)/(x2-x1). We substitute and get m=(26-12)/(11-4). This simplifies to m = 2. We can then use the point-slope form y-y1 = m(x-x1). We substitute and get y - 12 = 2(x - 4). We distribute: y - 12 = 2x - 8. We add 12 to both sides to get our final answer, y = 2x + 4.
<span>y is a function of x in y = 3x^3</span>
<u>Given</u><u> info</u><u>:</u><u>-</u> Find the remainder when x^5 - 3x^3 + x - 5 is divided by x - 2
<u>Solution:</u><u>-</u>
Given,
p(x) = x^5 - 3x^3 + x - 5 , g(x) = x - 2
Let g(x) = x-2 will be the factor of p(x) if p(2) = 0.
Now, p(x) = x^5 - 3x^3 + x - 5
p(2) = (2)^5 - 3(2)^3 + 2 - 5
= (2*2*2*2*2) - 3(2*2*2) + 3 - 5
= 32 - 3(8) + 3 - 5
= 32 - 24 + 3 - 5
= 31 - 24 - 2
= 31 - 26
= 5 Remainder.
Hence, when x^5 - 3x^3 + x - 5 is divided by x - 2 , we get the remainder as 5.
Answer:
54
Step-by-step explanation:
This can be divided into triangle ABF and trapezoid BCDE.
A = A₁ + A₂
A = ½ (10) (3) + ½ (6 + 7) (6)
A = 15 + 39
A = 54
The area is 54 square units.