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3 years ago

The graph of function h is shown (in the picture)

Mathematics

2 answers:

irga5000 [103]3 years ago

6 0

Answer:

Are you sure that the parts in the brackets are supposed to be in the equation? Because I think you might have to get rid of the inequalities before you put them in the graph. Also, I got rid of the bracketed inequalities and just left the equation and I got them to intersect.

Step-by-step explanation:

vivado [14]3 years ago

3 0

Answer:

You need to redo it you made a mistake I have had this before and it did the same thing then you will see what you made a mistake at.

Step-by-step explanation:

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3 years ago

Solve the following equation for y: −8x+ 4y = 20

MrRissso [65]

Answer:

y=5+2x

Normally I would explain it, but im in a bit of a hurry today. I apologize for the inconvenience!

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3 years ago

Describe the relationship between the<br> values of the digits in the number

Lelechka [254]

Answer:

Step-by-step explanation:

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3 years ago

This as a decimal 6th

makkiz [27]

Answer:

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3 years ago

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the

MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

6 0

3 years ago