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2 years ago

Can someone help me ?

Mathematics

2 answers:

aliina [53]2 years ago

8 0

Hola User_______________

Here IS YOUR Answer...!!!

_______________________

A.) 5.) 2/3 × 2/3 × 2/3 = (2/3)^3

6.) 4 × 4 × 4 = (4)^3

B.) 8.) (0.25) × (0.25) × (0.25)

9.) (1/9)×(1/9)×(1/9)

C.)

11.)3^3 = 9 and 4^3 = 64

12.)(4)^6 miles = 4096 miles

marin [14]2 years ago

7 0

Answer:

Step-by-step explanation:

12.)(4)^6 miles = 4096 miles

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belka [17]

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2 years ago

Question 1 (1 point)

taurus [48]

Answer:

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Step-by-step explanation:

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1 year ago

Read 2 more answers

I need help simplifying this problem:

Aliun [14]

C(t)= -0.3t^2 + 7.2t - 3.2

12c = 40

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2 years ago

Which shows the terms of the series? 4 12 48 192 4 12 36 3 12 48 192 3 12 48

Stells [14]

The value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

<h3>What is summation?</h3>

In mathematics, the summation is the addition of a sequence of any kind of numbers, called addends or summands.

Now we have a given term

$\sum_{n=1}^{4} 3(4)^{n-1}$

By solving the above term;

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^{1-1}+3(4)^{2-1}+3(4)^{3-1}+3(4)^{4-1}$

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^0+3(4)^1+3(4)^2+3(4)^3$

$\sum_{n=1}^{4} 3(4)^{n-1}=3 + 12 +48 + 192$

Hence the value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

To know more about Summation follow

brainly.com/question/2767605

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1 year ago

I need to find the volume of a nose cone.

rjkz [21]

well then, the volume of the nose cone will just be the sum of the volume of the cylinder below and the cone above.

since the diameter for both is 8, then their radius is half that, or 4.

$\bf \stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=4\\ h=6 \end{cases}\implies V=\cfrac{\pi (4)^2(6)}{3}\implies V=32\pi \\\\\\ \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=4\\ h=6 \end{cases}\implies V=\pi (4)^2(6)\implies V=96\pi \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of the nose cone}}{32\pi +96\pi \implies 128\pi }\qquad \approx \qquad 402.12$

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2 years ago