Question

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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

radius=10cm

<A0B=90°

Length of arc AB,

$10 \times \frac{\pi}{2 } = 5 \times 3.14 = 15.4cm$

$perimeter \: of \: quadrant = \: 10 + 10 + 15.4 = 35.4cm$

Area of quadrant=

$\frac{90}{360 } \times 3.14 \times {10 }^{2} = 78.5cm ^{2}$