9.
By the Segment Addition Postulate, SAP, we have
XY + YZ = XZ
so
YZ = XZ - XY = 5 cm - 2 cm = 3 cm
10.
M is the midpoint of XZ=5 cm so
XM = 5 cm / 2 = 2.5 cm
11.
XY + YM = XM
YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm
12.
The midpoint is just the average of the coordinate A(-3,2), B(5,-4)
Answer: M is (1,-1)
You'll have to plot it yourself.
13.
For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.
Answer: AB=10
M is the midpoint of AB so
Answer: AM=MB=5
14.
B is the midpoint of AC. We have A(-3,2), B(5,-4)
B = (A+C)/2
2B = A + C
C = 2B - A
C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)
Check the midpoint of AC:
(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good
Answer: C is (13, -10)
Again I'll leave the plotting to you.
Answer:
Table one respresents a function
Step-by-step explanation:
The reason is because the other 3 tables have two of the same x inputs but having a different out put
Hope this helps
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 8
Putting x=1.5 in Eqn 1
Dividing both sides by 8
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
Learn more about elimination method at:
#LearnwithBrainly
Answer:
Javier’s account has $282.5 at the end of the three months.
Step-by-step explanation:
final = initial - 7.5x
initial is the initial amount of money in the account, so 305. x is the number of months that have passed. Since Javier doesn't deposit any more money durning that time, the amount in the bank will always be less than 500 we don't have to consider anything else. We just sub initial with 305 and x ( the number of months) with 3 to get the answer. So,
final = 305 - 7.5 * 3 = 282.5
42,362 multiplied by 81 games gives 3,431,322 total tickets.
