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3241004551 [841]
3 years ago
8

For how many miles is the cost the same at both companies

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

You have not put any answers!

Step-by-step explanation:

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X equals 62 because you take 147 and subtract it from 180 and that gives you 33.
then you add 33 and 85 together to give you 118.  Then you subtract 118 from 180 and that gives you 62.
x=62
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Which term is a perfect square of the root 3x4?<br>​
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2√3

Step-by-step explanation:

√3x4 = √12 = 2√3

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The team loses fifteen yards in a row
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Fiona is drawing polygons on a computer. She wants to map a regular 9-sided polygon back onto itself using a reflection. Which s
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any perpendicular bisector of one of the sides".

We can define a line of reflection as the line in which a shape is reflected, or we can say that it is the mirror in which the shape is reflected. The line of reflection is the perpendicular bisector of any pair of corresponding points. If you want to join sets of corresponding points on the object and image, then

Step-by-step explanation:

3 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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