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3 years ago

-(3x squared) simplified

Mathematics

1 answer:

lana66690 [7]3 years ago

8 0

Answer:

-3x^2

Step-by-step explanation:

We must do the 'work' inside the parentheses first:

(3x squared) works out to 3x^2

after which we preface this result with the ' - ' sign: -3x^2

Note: if we write ONLY 3x squared the correct interpretation is 3x^2. But if we write (3x) squared, the correct interpretation is 9x^2. Double check the original problem, please, or (better yet) share an image of the original problem.

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Write the slope intercept form of 11x-8y=-48

bija089 [108]

Y=(11/8)x+6
subtract the 8y to the right then add the 48 to the left then divide by 8

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4 years ago

An acute angle θ is in a right triangle with sin θ = seven eighths. What is the value of cot θ?

olga2289 [7]

Draw a right triangle ABC, with m(CAB)=∅.

Let CB=7 units, AC=8 units, so by the Pythagorean theorem:

$AB= \sqrt{ AC^{2} - BC^{2} }= \sqrt{ 8^{2} - 7^{2} }= \sqrt{64-49} = \sqrt{15}$ (units)

so we have drawn a triangle where sin∅=7/8

in this triangle, cot∅=(adjacent side)/(opposite side)= $\frac{ \sqrt{15} }{7}$

Answer: <span>square root of fifteen divided by seven</span>

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3 years ago

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Vika [28.1K]

It's the second answer.

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3 years ago

Read 2 more answers

In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ

son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

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3 years ago

find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)

IceJOKER [234]

(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²

Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²

143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :

circumference of a circle = 2π.R = 2.π.12 = 75.41 m

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3 years ago