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3 years ago

I am very confused with this problem please help me

Mathematics

2 answers:

Tanya [424]3 years ago

6 0

Answer:

The answer is -0.5

Step-by-step explanation:

Divide both side by the numeric factor on the left side then solve

RideAnS [48]3 years ago

5 0

The answer to this problem is X= -1/2, -11/2

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Nathan launches a water balloon vertically from a platform on his roof. The height of the balloon (in feet) is represented by th

bulgar [2K]

Answer:

45.27feet

Step-by-step explanation:

Given the height of the balloon (in feet) represented by the equation h=−16t2+28.7t+32.4, where t is the time (in seconds)

Note that the velocity of the balloon at maximum height is zero, hence;

v = dh/dt =0

-32t+28.7 = 0

-32t = -28.7

t = 28.7/32

t = 0.897secs

Get the maximum height

Recall that h=−16t²+28.7t+32.4

h = -16(0.897)²+28.7(0.897)+32.4

h= -12.87+25.74+32.4

h = 45.27feet

Hence the maximum height reached is 45.27feet

7 0

2 years ago

Please Help Me! I will give brainly!!

DerKrebs [107]

Answer:

5 1/10 meters

Step-by-step explanation:

18 4/5 can be changed to 18 8/10 so

18 8/10 - 13 7/10 = 5 1/10 meters

8 0

2 years ago

Read 2 more answers

A man that is 6 feet tall is standing so that the tip of his shadow is 20 feet from a light pole. His shadow is 8 feet long. Wha

pychu [463]

Answer:

The answer to your question is: the height of the light pole is 15 ft.

Step-by-step explanation:

See the picture below

Now, we can do proportions to finds the height of the light pole

$\frac{20}{8} = \frac{x}{6}$

Solve for x

x = 6(20) / 8

x = 120 / 8

x = 15 ft

4 0

3 years ago

the ratio of the number of adults to the number of children in a library is 12:5 if there are 45 children in the library how my

anygoal [31]

I’m guessing 108. 45 divided by 5 is 9, so 9 times 12 is 108.

5 0

3 years ago

Read 2 more answers

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago